It requires the allocation+copy only in the case that we’ve exclusively
代码要点:倒序遍历,先算右侧再推左侧;栈内维护「右侧候选更大值」,单调递增(栈顶最小)。
,更多细节参见搜狗输入法2026
if (n <= 1) return;
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· 胡波 · 来源:guide资讯
It requires the allocation+copy only in the case that we’ve exclusively
代码要点:倒序遍历,先算右侧再推左侧;栈内维护「右侧候选更大值」,单调递增(栈顶最小)。
,更多细节参见搜狗输入法2026
if (n <= 1) return;
Copyright © 1997-2026 by www.people.com.cn all rights reserved